GCSE Maths · Ratio, proportion & rates of change

Compound Measures

Speed, density and pressure, and other rates - converting units and rearranging the formulae.

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Compound Measures, explained point by point

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  1. Use speed = distance ÷ time, and rearrange it

    Speed is distance shared over time: 150 miles in 2.5 hours is 60 mph. Rearrange for whichever is missing: distance = speed × time, time = distance ÷ speed. Times must be in the right form - 20 minutes is 13 hour, not 0.2 hours.

  2. Use density = mass ÷ volume

    Density says how much mass is packed into each unit of volume: 540 g in 200 cm³ is 2.7 g/cm³. Rearrange the same way as speed: mass = density × volume, volume = mass ÷ density. The units in the answer follow from the units you fed in.

  3. Use pressure = force ÷ area

    Pressure spreads a force over an area: a 300 N force on 0.5 m² gives 600 N/m². The same triangle of rearrangements applies. Intuition check: the same force on a SMALLER area gives a bigger pressure - that is why drawing pins work.

  4. Convert between compound units - m/s to km/h, g/cm³ to kg/m³

    Convert one unit at a time. For 20 m/s to km/h: 20 m is 0.02 km, and 3600 seconds make an hour, so 20 × 3.6 = 72 km/h. Sense-check the direction - the number of km/h should be bigger than the number of m/s.

  5. Read average speed from a distance–time graph

    Average speed over a section is total distance ÷ total time - the gradient of the line joining the section's start and end. A stop (flat section) still counts its time, which drags the average down.

  6. Use velocity–time graphs: gradient for acceleration, area for distanceHigher only

    On a velocity–time graph the gradient is acceleration and the AREA under the graph is distance travelled. Split the area into triangles and rectangles (or trapezia) and add them up. A flat section means steady speed, not stopped - that is the distance–time trap.

Common mistakes in Compound Measures

The slips that cost marks year after year, and what to do instead.

  • Treating minutes as decimals of an hour, so 20 minutes becomes 0.2 hours.

    Divide minutes by 60: 20 minutes is 2060 = 13 of an hour, and 1 hour 30 minutes is 1.5 hours.

  • Multiplying when you should divide after rearranging, as in time = speed × distance.

    Start from speed = distance ÷ time and rearrange it: time = distance ÷ speed. So 150 miles at 60 mph takes 150 ÷ 60 = 2.5 hours.

  • Converting m/s to km/h in one step, such as multiplying by 60 or by 1000.

    Change one unit at a time: 20 m/s is 20 × 3600 = 72 000 m in an hour, which is 72 km/h. Multiplying by 3.6 does both steps at once.

  • Finding an average speed by averaging the speeds of each part of the journey.

    Use total distance ÷ total time. 60 km at 30 km/h takes 2 hours and 60 km at 60 km/h takes 1 hour, so the average is 120 ÷ 3 = 40 km/h, not 45.

  • Reading distance from the gradient of a velocity–time graph, or taking a flat section to mean stopped.Higher only

    On a velocity–time graph the area underneath is the distance and the gradient is the acceleration. A flat section means a steady speed.

Practice

Try a Compound Measures question

A GCSE-style original question from this topic. Have a go before you open the working - deciding on an answer first is what makes the working stick.

A car travels 90 km in 1 hour 30 minutes at a steady speed. Work out its speed in km/h.

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