Expanding Brackets flashcards
12 cards on Expanding Brackets: the key points, worked examples and the slips to watch. Swipe through them, or print them.
Card 1 of 12
Expanding Brackets
Expanding a single bracket
How do you expand a single bracket such as 3(2x + 5)?
Answer it in your head, then turn the card over.
Expanding a single bracket
Key points
- Multiply every term inside the bracket by the term outside.
- Keep each result's sign: 3(2x + 5) = 6x + 15.
- A letter outside multiplies too: x(x + 4) = x² + 4x.
7(3x − 4)
7 × 3x = 21x, and 7 × −4 = −28
So 7(3x − 4) = 21x − 28
Watch out
Multiplying only the first term: 3(2x + 5) is 6x + 15, not 6x + 5.
Expanding Brackets
A negative outside the bracket
What happens to the signs when a negative number is outside the bracket?
Answer it in your head, then turn the card over.
A negative outside the bracket
Key points
- The negative multiplies every term inside, so every sign inside is affected.
- Negative × positive = negative; negative × negative = positive.
- So −2(x − 4) = −2x + 8.
Expand −4(3x − 5)
−4 × 3x = −12x
−4 × −5 = +20
So −4(3x − 5) = −12x + 20
Watch out
−2(x − 4) is −2x + 8, not −2x − 8: the two negatives make a positive.
Expanding Brackets
Expressions, equations and identities
What is an identity, and how is it different from an equation and an expression?
Answer it in your head, then turn the card over.
Expressions, equations and identities
Key points
- An expression has no equals sign: 4x − 7.
- An equation is true only for some values of x, so it can be solved.
- An identity is true for every value of the letters, and uses ≡: 2(x + 3) ≡ 2x + 6.
- Expanding a bracket always gives an identity.
Show 3(x + 4) − 2x ≡ x + 12
3x + 12 − 2x = x + 12, whatever x is
Test x = 5: 3 × 9 − 10 = 17, and 5 + 12 = 17
Watch out
Trying to solve an identity: every value of x works, so there is no single answer.
Expanding Brackets
Expanding and simplifying
How do you expand and simplify an expression with more than one bracket?
Answer it in your head, then turn the card over.
Expanding and simplifying
Key points
- Expand each bracket on its own first, each on its own line if that helps.
- Keep the sign in front of a bracket with it: − 2(x − 5) multiplies by −2.
- Then collect like terms: the x terms together, the numbers together.
3(2x + 4) − 2(x − 5)
= 6x + 12 − 2x + 10
x terms: 6x − 2x = 4x; numbers: 12 + 10 = 22
= 4x + 22
Watch out
− 2(x − 5) is − 2x + 10: the minus belongs to the 2 and reaches both terms.
Expanding Brackets
Collecting like terms
Which terms can be collected together, and which cannot?
Answer it in your head, then turn the card over.
Collecting like terms
Key points
- Like terms have exactly the same letters and powers: 3x and 5x.
- x and x² are not like terms, so 3x + 5x² stays as it is.
- The coefficient is the number in front of the letter: 7 in 7y. On its own, y means 1y.
Simplify 4x² + 3x − x² + 5x − 2
x² terms: 4x² − x² = 3x²
x terms: 3x + 5x = 8x
= 3x² + 8x − 2
Watch out
Adding unlike terms: 3x + 5x² is not 8x³, or 8x².
Expanding Brackets
Expanding double brackets
How do you expand double brackets such as (x + 3)(x − 2)?
Answer it in your head, then turn the card over.
Expanding double brackets
Key points
- Every term in the first bracket multiplies every term in the second: four products.
- FOIL keeps track: First, Outer, Inner, Last.
- The two middle terms are like terms: collect them.
(x + 6)(x − 4)
x × x = x², x × −4 = −4x, 6 × x = 6x, 6 × −4 = −24
= x² − 4x + 6x − 24
= x² + 2x − 24
Watch out
Losing the sign of the last term: + 6 × − 4 is − 24.
Expanding Brackets
Squaring a bracket
How do you expand a squared bracket such as (x + 3)²?
Answer it in your head, then turn the card over.
Squaring a bracket
Key points
- Write it as the bracket times itself: (x + 3)(x + 3).
- Expand all four products: there is always a middle term.
- (x + a)² = x² + 2ax + a², so (x + 3)² = x² + 6x + 9.
(x − 7)²
= (x − 7)(x − 7)
= x² − 7x − 7x + 49
= x² − 14x + 49
Watch out
(x + 3)² is not x² + 9: try x = 1, where (1 + 3)² = 16 but 1 + 9 = 10.
Expanding Brackets
Double brackets with a number before x
How do you expand double brackets such as (2x + 3)(3x − 1)?
Answer it in your head, then turn the card over.
Double brackets with a number before x
Key points
- Exactly as before: every term times every term, four products.
- Multiply the numbers and the letters: 2x × 3x = 6x².
- Collect the two middle terms.
(2x + 3)(3x − 1)
2x × 3x = 6x², 2x × −1 = −2x, 3 × 3x = 9x, 3 × −1 = −3
= 6x² − 2x + 9x − 3
= 6x² + 7x − 3
Watch out
2x × 3x is 6x², not 6x: the two x's multiply as well as the numbers.
Expanding Brackets
Factorising with a common factor
How do you factorise an expression by taking out a common factor?
Answer it in your head, then turn the card over.
Factorising with a common factor
Key points
- Factorising is the reverse of expanding: it writes the expression as a product.
- Find the highest common factor of every term, numbers and letters.
- Put it outside the bracket; inside goes each term divided by it.
- Check by expanding your answer back out.
Factorise 12x² + 18x
The HCF of 12 and 18 is 6, and both terms contain x: take out 6x
12x² ÷ 6x = 2x and 18x ÷ 6x = 3
= 6x(2x + 3)
Watch out
Not fully factorised: 3(2x² + 3x) still has a common x inside, so it should be 3x(2x + 3).
Expanding Brackets
Factorising x² + bx + c
How do you factorise a quadratic of the form x² + bx + c?
Answer it in your head, then turn the card over.
Factorising x² + bx + c
Key points
- Find two numbers that multiply to c and add to b.
- If c is positive, both numbers have the sign of b; if c is negative, their signs differ.
- Write them in (x + p)(x + q), then expand to check.
x² − 3x − 10 into two brackets
Multiply to −10 and add to −3: the pair is 2 and −5
So x² − 3x − 10 = (x + 2)(x − 5)
Watch out
A pair that adds to b but does not multiply to c: x² + 7x + 12 is (x + 3)(x + 4), not (x + 6)(x + 1).
Expanding Brackets
The difference of two squares
How do you factorise a difference of two squares, such as x² − 25?
Answer it in your head, then turn the card over.
The difference of two squares
Key points
- One square is taken away from another, and there is no middle term.
- x² − a² = (x + a)(x − a).
- It works because the middle terms, +ax and −ax, cancel when you expand.
Example
x² − 81: 81 = 9², so (x + 9)(x − 9)
4x² − 9: 4x² = (2x)² and 9 = 3², so (2x + 3)(2x − 3)
Watch out
x² + 25 is a sum, not a difference: it does not factorise into two brackets.
Expanding Brackets
HigherExpanding three brackets
How do you expand a product of three brackets, such as (x + 2)(x − 1)(x + 3)?
Answer it in your head, then turn the card over.
Expanding three brackets
Key points
- Multiply two of the brackets together first.
- Then multiply every term of that result by the third bracket: six products.
- Collect like terms; a grid keeps every product in view.
(x + 2)(x − 1)(x + 3)
(x + 2)(x − 1) = x² + x − 2
× (x + 3): x³ + 3x² + x² + 3x − 2x − 6
= x³ + 4x² + x − 6
Check with x = 2: 4 × 1 × 5 = 20, and 8 + 16 + 2 − 6 = 20
Watch out
Dropping a product: the three terms of the first result each meet both terms of the last bracket.
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Put it into practice
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